document.write( "Question 217820: find the maximum area of a rectangle with a perimeter of 54 cenimeters \n" ); document.write( "
Algebra.Com's Answer #164153 by drj(1380)\"\" \"About 
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Find the maximum area of a rectangle with a perimeter of 54 centimeters.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Perimeter P means adding up all 4 sides of a rectangle or P=w+w+L+L=2(w+L) where w is the width and L is the Length.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Maximum Area A=w*L is when the rectangle is a square or \"A=s%5E2\" where s=w=L.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. So P=2(w+L)=2(s+s)=4s. \r
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\n" ); document.write( "\n" ); document.write( "Step 4. P=54=4s or s=54/4=13.5.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. \"A=s%5E2=13.5%5E2=182.25\".\r
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\n" ); document.write( "\n" ); document.write( "Step 6. ANSWER: Maximum area is 182.25 square centimeters.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "drjctu@gmail.com\r
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