document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28407>Question 28407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Second problem: (5x) times (5x) (to the third) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16414 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Directions on little brother's lesson is: Write each expression using a single exponet. Problem is: \r<BR>\n" );
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document.write( "1)(5x) (to the 2nd) times x (to the 6th) times x (to the third) <BR>\n" );
document.write( "=[(5x)^2]X (x^6) X (x^3)<BR>\n" );
document.write( "=25(x^2)(x^6)(x^3)<BR>\n" );
document.write( "=25[(x)^(2+6+3)] (when quantities of the same base are multiplied write the base and add the powers)<BR>\n" );
document.write( "=25 (x)^11\r<BR>\n" );
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document.write( "Second problem: (5x) times (5x) (to the third)<BR>\n" );
document.write( "2)(5x) times (5x) (to the third)<BR>\n" );
document.write( "=(5x)X[(5x)^3]<BR>\n" );
document.write( "=[(5x)^(1+3)] (when quantities of the same base are multiplied write the base and add the powers)<BR>\n" );
document.write( "=(5x)^4<BR>\n" );
document.write( "=(5^4)(x^4)<BR>\n" );
document.write( "=625(x^4)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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