document.write( "Question 217753: factor by grouping
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Algebra.Com's Answer #164113 by RAY100(1637) $\"\"$ $\"About$

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12a^3 -9a^2 +4a -3
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\n" ); document.write( "3a^2(4a -3) +1(4a-3)
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\n" ); document.write( ",,,,,,hard to visualize but if b=(4a-3),,,,this becomes 3a^2b +1b,,,,,or b(3a^2 +1),,,,which becomes by subst back,,,,(4a-3)(3a^2 +1)
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\n" ); document.write( "(4a-3)(3a^2 +1),,,,answer
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\n" ); document.write( "check,,,,FOIL,,,,12a^3 +4a -9a^2 -3,,,,,ok
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\n" ); document.write( "2p^3 +5p^2 +6p +15
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\n" ); document.write( "p^2(2p +5),,,,,+ 3(2p+5)
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\n" ); document.write( "(p^2 +3) (2p+5),,,,,,answer
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\n" ); document.write( "check,,,,FOIL,,,,,2p^3 +5p^2 +6p +15,,,,,ok
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\n" ); document.write( "after factoring by grouping,,,,,check to see if either of the factors can be factored further,,,,,in our problems,,,,no
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