document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=217754>Question 217754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Each angle of a regular polygon measures 174 degrees.  How many sides does it have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164108 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Remember  the  formula  for  the sum  of  the  interior  angles  of  a  polygon is<BR>\n" );
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document.write( "(n-2) * 180,,,,,,,,,,,,,,for  a  triangle  with  3  sides,,,,(3-2)(180)=180,,,,ok<BR>\n" );
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document.write( "however  the  individual  angles  is  the  sum  / n,,,,,,or<BR>\n" );
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document.write( "(n-2(180)/n<BR>\n" );
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document.write( "applying  this  to  174<BR>\n" );
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document.write( "(n-2)(180)/n = 174<BR>\n" );
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document.write( "(n-2)(180) = 174 n<BR>\n" );
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document.write( "180n -360 =174n<BR>\n" );
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document.write( "6n = 360<BR>\n" );
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document.write( "n=60,,,,,,answer<BR>\n" );
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document.write( "check,,,(n-2) (180) /n = 58 *180 / 60 = 174,,,,ok<BR>\n" );
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