document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=217738>Question 217738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. A club consist of 20 members. In how many ways can a committee of 4 be selected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164099 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A club consist of 20 members. In how many ways can a committee of 4 be selected?<BR>\n" );
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document.write( "The 1st choice is 1 of 20, then 1/19, 1/18, 1/17.<BR>\n" );
document.write( "That's 20*19*18*17 = 116280 possibilities.<BR>\n" );
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document.write( "But, since choosing A,B,C&D is the same as choosing D,C,A & B, it has to be divided by 4*3*2*1 = 24<BR>\n" );
document.write( "116280/24 = 4845<BR>\n" );
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