document.write( "Question 217609: a rectangular room has a permeter of 48 ft. the width is two-thirds of the length. what are the dimensions of the room? \n" ); document.write( "
Algebra.Com's Answer #164085 by MathTherapy(10858)\"\" \"About 
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a rectangular room has a permeter of 48 ft. the width is two-thirds of the length. what are the dimensions of the room?\r
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\n" ); document.write( "\n" ); document.write( "Let the length of the room be L. Then the width is \"2%2F3\" of L, or \"2L%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Since perimeter = 48, and perimeter = 2L + 2W, then we'll have: \"2L+%2B+2%2A%282L%2F3%29+=+48\", or, \"2L+%2B+4L%2F3+=+48\"\r
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\n" ); document.write( "\n" ); document.write( "6L + 4L = 144 ----- Multiply by LCD, 3\r
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\n" ); document.write( "\n" ); document.write( "10L = 144\r
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\n" ); document.write( "\n" ); document.write( "\"L+=+144%2F10+=+14.4\" ft.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, length of the room, or L = \"highlight_green%2814.4%29\" ft, and its width = \"2%2F3\" of \"14.4\" ft, or \"highlight_green%289.6%29\" ft.\r
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\n" ); document.write( "\n" ); document.write( "2L + 2W = 48\r
\n" ); document.write( "\n" ); document.write( "2(14.4) + 2(9.6) = 48\r
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\n" ); document.write( "\n" ); document.write( "28.8 + 19.2 = 48 (TRUE)
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