document.write( "Question 217678: If the complement of an angle is 50 degrees less than one-sixth of its supplement, find the measure of the angle. \n" ); document.write( "

Algebra.Com's Answer #164077 by RAY100(1637) $\"\"$ $\"About$

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Let x= angle
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\n" ); document.write( "Complement = 90-x
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\n" ); document.write( "Supplement = 180-x
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\n" ); document.write( "Given,,,,C= 1/6 S -50
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\n" ); document.write( "(90-x) = (1/6) (180-x) -50
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\n" ); document.write( "90-x = 30 -x/6 -50
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\n" ); document.write( "110 = 5x/6
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\n" ); document.write( "132 = x,,,,in degrees
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\n" ); document.write( "check, C=90-132=-42,,,,s=180-132=48
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\n" ); document.write( "-42 = 48/6 -50 = 8-50 =-42,,,,,ok
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