document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=217675>Question 217675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find threee consecutive integers such that the sum of the first plus one-third of the second plus three-fourths of the third is 6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164076 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let,,(x),,,(x+1),,,(x+2),,,be  3  consecutive  numbers<BR>\n" );
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document.write( "Given,,,,x + (1/3)(x+1) +(3/4)(x+2) = 6,,,,,multiply  thru  by  12<BR>\n" );
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document.write( "12x +4(x+1) +9(x+2) = 72<BR>\n" );
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document.write( "12x +4x +4 +9x +18 = 72<BR>\n" );
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document.write( "25x = 50<BR>\n" );
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document.write( "x=2,,,numbers =  2,,,3,,,4<BR>\n" );
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document.write( "check,,,,2+ 1/3(3) +3/4(4) = 2+1+3 =6,,,,,ok<BR>\n" );
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