document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29642>Question 29642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the complementary and supplementary angles of 3x degress </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16404 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles add to 90:<BR>\n" );
document.write( "3x + y = 90<BR>\n" );
document.write( "--> y = 90-3x<BR>\n" );
document.write( "--> complementary angle is 90-3x\r<BR>\n" );
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document.write( "Supplementary angles add to 180:<BR>\n" );
document.write( "3x + y = 180<BR>\n" );
document.write( "--> y = 180-3x<BR>\n" );
document.write( "--> supplementary angle is 180-3x\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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