document.write( "Question 217380: Mary Auburn makes three investm,ents. The investment that pays 12% is twice the amount of the account that pays 9%. The amount inveted at 10% is $500 more than the amount invested at 9%. If the annual interest income is $1555, how much money is invested at each rate?\r
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Algebra.Com's Answer #164030 by ankor@dixie-net.com(22740)\"\" \"About 
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three investments.
\n" ); document.write( "The investment that pays 12% is twice the amount of the account that pays 9%.
\n" ); document.write( "The amount inveted at 10% is $500 more than the amount invested at 9%.
\n" ); document.write( "If the annual interest income is $1555, how much money is invested at each rate?
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\n" ); document.write( "Let x = amt invested at 9%
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\n" ); document.write( "\"The investment that pays 12% is twice the amount of the account that pays 9%.\"
\n" ); document.write( "therefore:
\n" ); document.write( "2x = amt invested at 12%
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\n" ); document.write( "\"The amount invested at 10% is $500 more than the amount invested at 9%.\"
\n" ); document.write( "therefore:
\n" ); document.write( "(x+500) = amt invested at 10%
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\n" ); document.write( "If the annual interest income is $1555, how much money is invested at each rate?
\n" ); document.write( ".09x + .12(2x) + .10(x+500) = 1555
\n" ); document.write( ".09x + .24x + .10x + 50 = 1555
\n" ); document.write( ".43x = 1555 - 50
\n" ); document.write( ".43x = 1505
\n" ); document.write( "x = \"1505%2F.43\"
\n" ); document.write( "x = $3500 invested at 9%
\n" ); document.write( "then
\n" ); document.write( "2(2500) = $7000 invested at 12%
\n" ); document.write( "and
\n" ); document.write( "3500 + 500 = $4000 invested at 10%
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\n" ); document.write( "Is that true?
\n" ); document.write( ".09(3500) + .12(7000) + .10(4000)
\n" ); document.write( "315 + 840 + 400 = 1555
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