document.write( "Question 29688: Please help me solve this equation
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document.write( "x^4 + 12x^2 -64 = 0 \n" );
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Algebra.Com's Answer #16394 by ikdeep(226)![]() ![]() You can put this solution on YOUR website! x^4 + 12x^2 -64 = 0 \n" ); document.write( "(here you must know how we make factors i.e splitting of the middle term...if you might not know then please contact me again ,,and i will explain to you)...\r \n" ); document.write( "\n" ); document.write( "x^4 + (16-4)x^2 -64 = 0 ...by solving brackets..we get\r \n" ); document.write( "\n" ); document.write( "x^4 +16x^2 -4x^2 -64 = 0\r \n" ); document.write( "\n" ); document.write( "taking common from first two and last two variables...we get\r \n" ); document.write( "\n" ); document.write( "x^2(x^2 +16) -4 (x^2 +16)= 0 \r \n" ); document.write( "\n" ); document.write( "or (x^2-4) (x^2 +16) =0 \r \n" ); document.write( "\n" ); document.write( "Here further factorization can be possible,,,\r \n" ); document.write( "\n" ); document.write( "or [(x)^2 - (2)^2] (x^2 +16) =0 \r \n" ); document.write( "\n" ); document.write( "now , in first variables i.e.[(x)^2 - (2)^2] ,,,,,we can apply the formula \n" ); document.write( "(a^2 - b^2)= (a+b)(a-b)..... and we get \r \n" ); document.write( "\n" ); document.write( " [(x - 2)(x + 2}] (x^2 +16) =0 \r \n" ); document.write( "\n" ); document.write( "Please feel free to revert back for any further queries.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |