document.write( "Question 29682: sum of two numbers is 42 and their difference is 30. find each of the numbers. \n" ); document.write( "
Algebra.Com's Answer #16393 by ikdeep(226)\"\" \"About 
You can put this solution on YOUR website!
Let the first number = x
\n" ); document.write( "Let the second number = y \r
\n" ); document.write( "\n" ); document.write( "According first condition i.e sum of two numbers is 42 ...we get \r
\n" ); document.write( "\n" ); document.write( "x+y = 42............(1)\r
\n" ); document.write( "\n" ); document.write( "According second condition i.e difference of two numbers is 30 ...we get \r
\n" ); document.write( "\n" ); document.write( "x-y = 30.............(2)\r
\n" ); document.write( "\n" ); document.write( "on adding (1)and (2)..we get...\r
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\n" ); document.write( "\n" ); document.write( "x+y = 42
\n" ); document.write( "x-y = 30
\n" ); document.write( "--------
\n" ); document.write( "2x = 72 (+y and -y would be eliminated)\r
\n" ); document.write( "\n" ); document.write( "divide both side by 2 we get...\r
\n" ); document.write( "\n" ); document.write( "x = 72/2\r
\n" ); document.write( "\n" ); document.write( "x = 36\r
\n" ); document.write( "\n" ); document.write( ",,,to get the value of y, substitute the value of x either in (1) or in (2)...but here i took (1)....\r
\n" ); document.write( "\n" ); document.write( "x+y = 42............(1)\r
\n" ); document.write( "\n" ); document.write( "36 + y = 42\r
\n" ); document.write( "\n" ); document.write( "y = 42 - 36\r
\n" ); document.write( "\n" ); document.write( "y = 6 \r
\n" ); document.write( "\n" ); document.write( "so the values are x = 36 and y = 6......\r
\n" ); document.write( "\n" ); document.write( "To verify your answer you can put the value of x and y in either (1) or(2)
\n" ); document.write( "or in both and you will always get LHS = RHS\r
\n" ); document.write( "\n" ); document.write( "please feel free to revert back for any further queries.\r
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