document.write( "Question 29683: please illustrate the figure..\r
\n" ); document.write( "\n" ); document.write( "each side of a cube is increased by 1%. by what percent is the volume increased?..
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Algebra.Com's Answer #16391 by ikdeep(226)\"\" \"About 
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Let the side of the cube = 100 units
\n" ); document.write( "therefoere the volume of cube = (100)^3 (formula = side^3)
\n" ); document.write( " = 1000000 square units\r
\n" ); document.write( "\n" ); document.write( "Now when the side is increased by 1%....we get \r
\n" ); document.write( "\n" ); document.write( " The increased side of the cube = 101 units
\n" ); document.write( "(increased side is calculted like this = 100 +1%of 100)
\n" ); document.write( "( = 100 + 1/100 *100)
\n" ); document.write( "(= 100+1 )
\n" ); document.write( "(= 101 units)\r
\n" ); document.write( "\n" ); document.write( "Therefoere the increased volume of cube = (101)^3
\n" ); document.write( " = 1030301 square units\r
\n" ); document.write( "\n" ); document.write( "Increase in volume = new volume - original volume\r
\n" ); document.write( "\n" ); document.write( "= 1030301 - 1000000\r
\n" ); document.write( "\n" ); document.write( "= 30301 square units \r
\n" ); document.write( "\n" ); document.write( "% Increase in volume = Increase in volume / original volume *100\r
\n" ); document.write( "\n" ); document.write( "= 30301/1000000 * 100\r
\n" ); document.write( "\n" ); document.write( "= 3.0301 % or 3 % appoximately\r
\n" ); document.write( "\n" ); document.write( "please feel free to revert back for any further queries.\r
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