document.write( "Question 217335: Prove cot(45°-A) = \"+%28cotA+%2B+1%29%2F+%28cotA+-+1%29+\"
\n" ); document.write( "Hence show that cot15° = 2 + sqrt3
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Algebra.Com's Answer #163907 by jsmallt9(3758)\"\" \"About 
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cot(45°-A) = \"+%28cotA+%2B+1%29%2F+%28cotA+-+1%29+\"

\n" ); document.write( "There may be more clever ways of doing this but one approach to a lot of Trig. problems is to start by rewriting the expression in terms of sin and cos. Since cot(a) = cos(a)/sin(a):
\n" ); document.write( "cot(45°-A) = \"+cos%2845+-A%29%2Fsin%2845-A%29+\"
\n" ); document.write( "Now we can use the angle difference identitites: \"cos%28x-y%29+=+cos%28x%29%2Acos%28y%29+%2B+sin%28x%29%2Asin%28y%29\" and \"sin%28x-y%29+=+sin%28x%29%2Acos%28y%29+-+cos%28x%29sin%28y%29\" to rewrite the right side:
\n" ); document.write( "cot(45°-A) =
\n" ); document.write( "Since \"cos%2845%29+=+sin%2845%29+=+sqrt%282%29%2F2\":
\n" ); document.write( "cot(45°-A) =
\n" ); document.write( "We can reduce the fraction by factoring out \"sqrt%282%29%2F2\":
\n" ); document.write( "cot(45°-A) =
\n" ); document.write( "Now the \"%28sqrt%282%29%2F2%29\"'s cancel leaving:
\n" ); document.write( "cot(45°-A) = \"%28cos%28A%29+%2B+sin%28A%29%29%2F%28cos%28A%29-sin%28A%29%29\"
\n" ); document.write( "Looking at what we have and at where we want to be we can see that we're very close. All we need is sin(A) as a denominator of each term. So we multiply the top and bottom by \"1%2Fsin%28A%29\":
\n" ); document.write( "cot(45°-A) =
\n" ); document.write( "Using the Distributive Property we get:
\n" ); document.write( "cot(45°-A) =
\n" ); document.write( "which simplifies to
\n" ); document.write( "cot(45°-A) = \"+%28cot%28A%29+%2B+1%29%2F+%28cot%28A%29+-+1%29+\"

\n" ); document.write( "To find cot(15°): If we realize that 15 = 45-30 then we can use the formula above by setting A = 30:
\n" ); document.write( "cot(15°) = cot(45°-30) = \"+%28cot%2830%29+%2B+1%29%2F+%28cot%2830%29+-+1%29+\"
\n" ); document.write( "\"cot%2830%29+=+cos%2830%29%2Fsin%2830%29+=+%28sqrt%283%29%2F2%29%2F%281%2F2%29+=+sqrt%283%29\"
\n" ); document.write( "Substituting this we get:
\n" ); document.write( "cot(15°) = cot(45°-30) = \"+%28sqrt%283%29+%2B+1%29%2F+%28sqrt%283%29+-+1%29+\"
\n" ); document.write( "Next we rationalize the denominator. To do this we will use the conjugate of the denominator which is \"sqrt%283%29+%2B+1\":
\n" ); document.write( "cot(15°) = cot(45°-30) =
\n" ); document.write( "Multiplying this out (using either FOIL or the patterns for (a+b)(a+b) and (a+b)(a-b)) we get:
\n" ); document.write( "cot(15°) = cot(45°-30) =
\n" ); document.write( "cot(15°) = cot(45°-30) = \"%283+%2B+2sqrt%283%29+%2B+1%29%2F%283+-+1%29\"
\n" ); document.write( "See how the conjugate made the denominator rational?
\n" ); document.write( "cot(15°) = cot(45°-30) = \"%284+%2B+2sqrt%283%29%29%2F%282%29\"
\n" ); document.write( "Reduce the fraction by factoring out 2 and canceling:
\n" ); document.write( "cot(15°) = cot(45°-30) = \"%282%282+%2B+sqrt%283%29%29%29%2F%282%29\"
\n" ); document.write( "cot(15°) = cot(45°-30) = \"2+%2B+sqrt%283%29\"\r
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