document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216657>Question 216657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + 1 = -7y<BR>\n" );
document.write( "6x + 7y = 0\r<BR>\n" );
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document.write( "Solve for x and y. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163872 by </B><A HREF=/tutors/aboutme.mpl?userid=chibisan><B>chibisan(131)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chibisan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chibisan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve sitmultaneously <BR>\n" );
document.write( "3x + 7y = -1 -(1)<BR>\n" );
document.write( "6x + 7y = 0 -(2)\r<BR>\n" );
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document.write( "(1)-(2)<BR>\n" );
document.write( "(3x + 7y)(6x + 7y) = -1-0<BR>\n" );
document.write( "3x - 6x = -1<BR>\n" );
document.write( "-3x = -1 <BR>\n" );
document.write( "x = 1/3\r<BR>\n" );
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document.write( "finding y , subst x=1/3 to eq(1)<BR>\n" );
document.write( "3(1/3) + 1 = -7y<BR>\n" );
document.write( "2 = -7y<BR>\n" );
document.write( "y = -2/7 \r<BR>\n" );
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document.write( "x = 1/3 , y = -2/7 (ans) </SPAN>\n" );
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