document.write( "Question 216996: Find k that so that the line through (4,4) and (k,8) is
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document.write( "a) parallel to 3y-4x=7
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document.write( "b) perpendicular to 4y+5x=1 \n" );
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Algebra.Com's Answer #163857 by chibisan(131)![]() ![]() You can put this solution on YOUR website! a ) \n" ); document.write( "parallel = same grad \n" ); document.write( "3y= 7+4x \n" ); document.write( "make y the subject \n" ); document.write( "y= 7/3 + 4/3x \n" ); document.write( "grad = 4/3\r \n" ); document.write( "\n" ); document.write( "grad of line through (4,4) and (k,8) . leave k as it is \n" ); document.write( "grad = 4-8 / 4-k \n" ); document.write( "4/3 = -4 / 4-k \n" ); document.write( "cross multiply it , \n" ); document.write( "16-4k=-12 \n" ); document.write( "16+12 = 4k \n" ); document.write( "k = 7 (ans)\r \n" ); document.write( "\n" ); document.write( "b) \n" ); document.write( "perpendicular = negative reciprocal \n" ); document.write( "4y+5x=1 \n" ); document.write( "make y the subject always. \n" ); document.write( "4y=1-5x \n" ); document.write( "y= 1/4 - 5/4x \n" ); document.write( "grad= -5/4 \n" ); document.write( "perpendicular grad = 4/5 \r \n" ); document.write( "\n" ); document.write( "from previous steps , -4/4-k is the grad so , \n" ); document.write( "4/5 = -4/4-k \n" ); document.write( "cross multiply , \n" ); document.write( "16 - 4k = -20 \n" ); document.write( "16+20 = 4k \n" ); document.write( "k = 9 (ans) \n" ); document.write( " \n" ); document.write( " |