document.write( "Question 217213: The length of a rectangle is 4in longer than its width. If the perimeter of the rectangle is 28in, find its area. \n" ); document.write( "
Algebra.Com's Answer #163811 by ichudov(507)\"\" \"About 
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Keep in mind that perimeter is 2*length plus 2*width.\r
\n" ); document.write( "\n" ); document.write( "\"system%28+length+=+width%2B4%2C+2%2Alength%2B2%2Awidth+=+28+%29+\"\r
\n" ); document.write( "\n" ); document.write( "This is a linear system: \r
\n" ); document.write( "\n" ); document.write( "\"system%28+length+-width+=+4%2C+2%2Alength%2B2%2Awidth+=+28+%29+\"\r
\n" ); document.write( "\n" ); document.write( "which you can solve with the linear solver\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " We'll use substitution. After moving -1*width to the right, we get:
\n" ); document.write( " \"1%2Alength+=+4+-+-1%2Awidth\", or \"length+=+4%2F1+-+-1%2Awidth%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"2%2A%284%2F1+-+-1%2Awidth%2F1%29+%2B+2%5Cwidth+=+28\" and simplify: So, we know that width=5. Since \"length+=+4%2F1+-+-1%2Awidth%2F1\", length=9.
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\n" ); document.write( " Answer: \"system%28+length=9%2C+width=5+%29\".
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