document.write( "Question 217217: Factor:
\n" ); document.write( "(4x^3)-(24x^2)-x+6 \n" ); document.write( "

Algebra.Com's Answer #163795 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( " $\"4x%5E3-24x%5E2-x%2B6\"$ Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( " $\"%284x%5E3-24x%5E2%29%2B%28-x%2B6%29\"$ Group like terms\r
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\n" ); document.write( "\n" ); document.write( " $\"4x%5E2%28x-6%29-1%28x-6%29\"$ Factor out the GCF $\"4x%5E2\"$ out of the first group. Factor out the GCF $\"-1\"$ out of the second group\r
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\n" ); document.write( "\n" ); document.write( " $\"%284x%5E2-1%29%28x-6%29\"$ Since we have the common term $\"x-6\"$ , we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( " $\"%282x%2B1%29%282x-1%29%28x-6%29\"$ Factor $\"4x%5E2-1\"$ using the difference of squares to get $\"%282x%2B1%29%282x-1%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "So $\"4x%5E3-24x%5E2-x%2B6\"$ factors to $\"%282x%2B1%29%282x-1%29%28x-6%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "In other words, $\"4x%5E3-24x%5E2-x%2B6=%282x%2B1%29%2A%282x-1%29%2A%28x-6%29\"$
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