document.write( "Question 216764: I guess that I need help with this one too!\r
\n" ); document.write( "\n" ); document.write( "A bacteria population doubles every four minutes. If the population begins with one cell, how long will it take to grow to 1,024 cells?\r
\n" ); document.write( "\n" ); document.write( "I know I need to use this formula A=Pe^rt or at least I think so.
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Algebra.Com's Answer #163791 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A bacteria population doubles every four minutes. If the population begins with one cell, how long will it take to grow to 1,024 cells?
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\n" ); document.write( "1024 is 2^10, so there must be 10 doublings.
\n" ); document.write( "10*4 = 40 minutes.
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\n" ); document.write( "Call 4 minutes the period:
\n" ); document.write( "P #
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\n" ); document.write( "0 1
\n" ); document.write( "1 2
\n" ); document.write( "2 4
\n" ); document.write( "3 8
\n" ); document.write( "4 16
\n" ); document.write( "5 32
\n" ); document.write( "6 64
\n" ); document.write( "7 128
\n" ); document.write( "8 256
\n" ); document.write( "9 512
\n" ); document.write( "10 1024
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\n" ); document.write( "1024 is commonly called 1K, as in computer memory (K is for kilo).
\n" ); document.write( "1K = 1024 bits or bytes.
\n" ); document.write( "1 Meg = 1,048,576 = 2^20
\n" ); document.write( "1 Gig = 1,073,741,824 = 2^30
\n" ); document.write( "1 Tera = a lot, I think it's 10^40
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\n" ); document.write( "Another approach to the problem (remember the problem?) is:
\n" ); document.write( "log(1024)/log(2) = 10 = # of periods
\n" ); document.write( "We divide by the log of 2 because in each period the # is multiplied by 2. If the bacteria tripled each period, we would divide by log of 3, etc.
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