document.write( "Question 216764: I guess that I need help with this one too!\r
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document.write( "A bacteria population doubles every four minutes. If the population begins with one cell, how long will it take to grow to 1,024 cells?\r
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document.write( "I know I need to use this formula A=Pe^rt or at least I think so. \n" );
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Algebra.Com's Answer #163791 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A bacteria population doubles every four minutes. If the population begins with one cell, how long will it take to grow to 1,024 cells? \n" ); document.write( "---------------------- \n" ); document.write( "1024 is 2^10, so there must be 10 doublings. \n" ); document.write( "10*4 = 40 minutes. \n" ); document.write( "----------- \n" ); document.write( "Call 4 minutes the period: \n" ); document.write( "P # \n" ); document.write( "---- \n" ); document.write( "0 1 \n" ); document.write( "1 2 \n" ); document.write( "2 4 \n" ); document.write( "3 8 \n" ); document.write( "4 16 \n" ); document.write( "5 32 \n" ); document.write( "6 64 \n" ); document.write( "7 128 \n" ); document.write( "8 256 \n" ); document.write( "9 512 \n" ); document.write( "10 1024 \n" ); document.write( "--------- \n" ); document.write( "1024 is commonly called 1K, as in computer memory (K is for kilo). \n" ); document.write( "1K = 1024 bits or bytes. \n" ); document.write( "1 Meg = 1,048,576 = 2^20 \n" ); document.write( "1 Gig = 1,073,741,824 = 2^30 \n" ); document.write( "1 Tera = a lot, I think it's 10^40 \n" ); document.write( "--------------------------- \n" ); document.write( "Another approach to the problem (remember the problem?) is: \n" ); document.write( "log(1024)/log(2) = 10 = # of periods \n" ); document.write( "We divide by the log of 2 because in each period the # is multiplied by 2. If the bacteria tripled each period, we would divide by log of 3, etc. \n" ); document.write( " |