document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216768>Question 216768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a pipe with a circumference of 8 cm and length of 20 cm and that 8 turns of a wire are wrapped around the pipe. What is the length of the wire?\r<BR>\n" );
document.write( "\n" );
document.write( "The wire is wrapped around this cylinder in somewhat a diagonal from the top to the bottom. The wire does not cover the top or the bottom.\r<BR>\n" );
document.write( "\n" );
document.write( "While working, I thought I should just multiply the 8 turns by the 8 cm circumference, but that does not give me the correct answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163787 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a pipe with a circumference of 8 cm and length of 20 cm and that 8 turns of a wire are wrapped around the pipe. What is the length of the wire? <BR>\n" );
document.write( "The wire is wrapped around this cylinder in somewhat a diagonal from the top to the bottom. The wire does not cover the top or the bottom. <BR>\n" );
document.write( "While working, I thought I should just multiply the 8 turns by the 8 cm circumference, but that does not give me the correct answer.<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "The wire will form a helix.  Each turn will advance along the pipe 1/8 of the length.<BR>\n" );
document.write( "20/8 = 2.5 cm<BR>\n" );
document.write( "Each turn will be similar to a right triangle with a base of 20 cm and a height of 2.5 cm.  The hypotenuse will be sqrt(20^2 + 2.5^2) = sqrt(406.25)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "* </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );