document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=217173>Question 217173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you answer 3B and the matrices for B is -5,12<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163781 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To compute 3B, simply multiply <u>every</u> entry in the matrix B by 3. \r<BR>\n" );
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document.write( "In other words, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3B=3%2A%28matrix%282%2C2%2C-5%2C12%2C0%2C3%29%29=%28matrix%282%2C2%2C3%28-5%29%2C3%2812%29%2C3%280%29%2C3%283%29%29%29=%28matrix%282%2C2%2C-15%2C36%2C0%2C9%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3B=%28matrix%282%2C2%2C-15%2C36%2C0%2C9%29%29 ALIGN=MIDDLE  ALT=\"3B=%28matrix%282%2C2%2C-15%2C36%2C0%2C9%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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