document.write( "Question 217100: Solve by Cramer's Rule x=dx/d, y=dy/d, and z=dz/d\r
\n" ); document.write( "\n" ); document.write( "2x-y+3z=9
\n" ); document.write( "x+4y+4z=5
\n" ); document.write( "3x+2y+2z=5\r
\n" ); document.write( "\n" ); document.write( "I have worked this problem and I know it is not right because of the numbers I am getting. I do have that D is -40. I have dx is -20. I have dy is 210 and dz is 156. Something is not right in the way I set up teh matrix. Thanks for your help.
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Algebra.Com's Answer #163741 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
D is -40
\n" ); document.write( "----------
\n" ); document.write( "For Dx:
\n" ); document.write( "|9 -1 3|
\n" ); document.write( "|5 +4 4|
\n" ); document.write( "|5 +2 2|\r
\n" ); document.write( "\n" ); document.write( "= 9(8-8) + 1(10-20) + 3(10-20)
\n" ); document.write( "= -10 -30
\n" ); document.write( "= -40
\n" ); document.write( "x = +1
\n" ); document.write( "------
\n" ); document.write( "For Dy:
\n" ); document.write( "|2 9 3|
\n" ); document.write( "|1 5 4|
\n" ); document.write( "|3 5 2|\r
\n" ); document.write( "\n" ); document.write( "= 2(10-20) - 9(2-12) + 3(5-15)
\n" ); document.write( "= -20 +90 -30 = +40
\n" ); document.write( "y = -1
\n" ); document.write( "-------
\n" ); document.write( "For Dz:
\n" ); document.write( "|2 -1 9|
\n" ); document.write( "|1 +4 5|
\n" ); document.write( "|3 2 5|\r
\n" ); document.write( "\n" ); document.write( "= 2(20-10) + 1(5-15) + 9(2-12)
\n" ); document.write( "= 20 - 10 -90
\n" ); document.write( "= -80
\n" ); document.write( "z = 2
\n" ); document.write( "
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