document.write( "Question 216936: The sum of three consecutive odd integers is 16 more than the greatest of the integers. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #163696 by Earlsdon(6294) $\"\"$ $\"About$

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Let the first odd integer be (2n+1) where n is any integer, the (2n+3) is the next consecutive odd integer and (2n+5) is the third consecutive odd integer.
\n" ); document.write( "The sum of these is 16 more than the third (largest) of the integers.
\n" ); document.write( " $\"%282n%2B1%29%2B%282n%2B3%29%2B%282n%2B5%29+=+%282n%2B5%29%2B16\"$ Simplify.
\n" ); document.write( " $\"6n%2B9+=+2n%2B21\"$ Subtract 2n from both sides.
\n" ); document.write( " $\"4n%2B9+=+21\"$ Subtract 9 from both sides.
\n" ); document.write( " $\"4n+=+12\"$ Divide both sides by 4.
\n" ); document.write( " $\"n+=+3\"$ so...
\n" ); document.write( " $\"2n%2B1+=+7\"$
\n" ); document.write( " $\"2n%2B3+=+9\"$
\n" ); document.write( " $\"2n%2B5+=+11\"$
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