document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216890>Question 216890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three consecutive odd numbers, such that three times the 1st is the sum of the 2nd and 3rd .\r<BR>\n" );
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document.write( "If you use algebra which I did, you get three even numbers 3x = (x+2)+(x+4) <BR>\n" );
document.write( "what's the solution then? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163693 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three consecutive odd numbers, such that three times the 1st is the sum of the 2nd and 3rd . <BR>\n" );
document.write( "If you use algebra which I did, you get three even numbers 3x = (x+2)+(x+4) <BR>\n" );
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document.write( "3x = x+2 + x+4 = 2x+6<BR>\n" );
document.write( "x = 6<BR>\n" );
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document.write( "3*6 is 8+10<BR>\n" );
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document.write( "They have to be even numbers.  The sum of any 2 odd numbers is an even number, and the sum of any 2 even numbers is also even.<BR>\n" );
document.write( "In other words, there are no odd numbers that fit. </SPAN>\n" );
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