document.write( "Question 216635: A canoe is paddled at 4km/h directly across a river that flows at 3kh/h. (a) what is the resultant speed of the canoe? (b) How fast and in what direction can the canoe be paddled to reach a destination directly across the river. \n" ); document.write( "
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A canoe is paddled at 4km/h directly across a river that flows at 3kh/h. (a) what is the resultant speed of the canoe? (b) How fast and in what direction can the canoe be paddled to reach a destination directly across the river.
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\n" ); document.write( "It's sqrt(4^2 + 3^2)
\n" ); document.write( "= 5 kph
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\n" ); document.write( "(b) How fast and in what direction can the canoe be paddled to reach a destination directly across the river.
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\n" ); document.write( "The canoe's heading has to be upstream.
\n" ); document.write( "The angle of the heading depends on the speed of the canoe (if the speed of the stream is fixed).
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\n" ); document.write( "The sine of the angle of \"crabbing\" is 3/speed of the canoe.
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\n" ); document.write( "If as in the example, the canoe is paddled at 4 kph, then the angle will be
\n" ); document.write( "arcsin(3/4) = ~ 48.59 degs
\n" ); document.write( "If it's paddled 10 kph, then the angle will be 17.46 degs.
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