document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216632>Question 216632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the distance between points at (m +4, n) and (m, n-3)\r<BR>\n" );
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document.write( "a)3.5<BR>\n" );
document.write( "b)5<BR>\n" );
document.write( "c)1<BR>\n" );
document.write( "d)7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163565 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The  distance  formula  is,,d =sqrt{ (y2-y1)^2 + (x2-x1)^2 }<BR>\n" );
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document.write( "subst  for,,,(m+4,n),,,,,(m, n-3)<BR>\n" );
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document.write( "d=sqrt{(4)^2 + (3)^2} = sqrt{ 16+9} = sqrt{25} = 5,,,,,which  is  answer  (b)<BR>\n" );
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