document.write( "Question 216553: A line is described by the equation y = 3 . A parabola is given by the equation Y = x^2 –6x +c What value(s) of c would result in this system of equations having one solution? What value(s) of c would result in two solutions? \n" ); document.write( "
Algebra.Com's Answer #163515 by Theo(13342)\"\" \"About 
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I'm not sure I understand the question.
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\n" ); document.write( "If you want to solve these equations simultaneously, then you would have:
\n" ); document.write( "y = 3
\n" ); document.write( "y = x^2 - 6x + c
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\n" ); document.write( "you would substitute 3 for y in the second equation to get:
\n" ); document.write( "3 = x^2 - 6x + c
\n" ); document.write( "If you subtract 3 from both sides of this equation, you would get:
\n" ); document.write( "x^2 - 6x + c - 3 = 0
\n" ); document.write( "If you consider a solution to this equation as finding the roots of this equation, then you can get no roots, one root, or two roots.
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\n" ); document.write( "There are several ways to find the roots of this equation.
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\n" ); document.write( "One way is to use the quadratic formula of \"x+=+%28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
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\n" ); document.write( "If the number under the square root sign is 0, you will have one root.
\n" ); document.write( "If the number under the square root sign is positive, you will have two roots.
\n" ); document.write( "If the number under the square root sign is negative, you will have no roots.
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\n" ); document.write( "The standard form of a quadratic equation is:
\n" ); document.write( "y = ax^2 + bx + c = 0
\n" ); document.write( "Your equation is:
\n" ); document.write( "y = x^2 - 6x + c - 3 = 0
\n" ); document.write( "The a term is equal to 1
\n" ); document.write( "The b term is equal to -6
\n" ); document.write( "The c term is equal to c-3
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\n" ); document.write( "To get one root, you want b^2 - 4ac to equal to 0
\n" ); document.write( "You have:
\n" ); document.write( "(-6)^2 - 4*1*(c-3)
\n" ); document.write( "Expanding this out, you have:
\n" ); document.write( "36 - 4c + 12 = 48-4c
\n" ); document.write( "Set this equal to 0 and you have:
\n" ); document.write( "48 - 4c = 0 which becomes 4c = 48 which becomes c = 12
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\n" ); document.write( "If c = 12, you will have one root.
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\n" ); document.write( "Your original equation becomes:
\n" ); document.write( "3 = x^2 - 6x + 12
\n" ); document.write( "Subtract 3 from both sides to get x^2 - 6x + 9 = 0
\n" ); document.write( "Factor this to get:
\n" ); document.write( "(x-3)^2 = 0
\n" ); document.write( "Take the square root of both sides of this equation to get x-3 = 0.
\n" ); document.write( "Add 3 to both sides of this equation to get x = 3
\n" ); document.write( "Your one root is x = 3
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\n" ); document.write( "A graph of x^2 - 6x + 9 is shown below:
\n" ); document.write( "\"graph+%28200%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2+-+6x+%2B+9%29\"
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\n" ); document.write( "Since \"b%5E2+-+4ac+=+0\", then if you make c bigger, it will become negative and if you make c smaller, it will become positive.
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\n" ); document.write( "to get two roots, make c smaller.
\n" ); document.write( "Something like 6 would be fine.
\n" ); document.write( "A graph of x^2 - 6x + 6 is shown below:
\n" ); document.write( "\"graph+%28200%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2+-+6x+%2B+6%29\"
\n" ); document.write( "As you can see the equation shown above has two roots.
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\n" ); document.write( "to get no roots, make c larger.
\n" ); document.write( "Something like 12 would be fine.
\n" ); document.write( "A graph of x^2 - 6x + 12 is shown below:
\n" ); document.write( "\"graph+%28200%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2+-+6x+%2B+12%29\"
\n" ); document.write( "As you can see the equation shown above has no roots because it does not cross the x-axis where the roots would be.
\n" ); document.write( "You actually get solutions when you solve for the roots, but the solut9ions are not real because they contain imaginary numbers which are products of the square root of a negative number. These are not considered roots.
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\n" ); document.write( "To find the roots of the second and third example, just plug the numbers into the quadratic formula and you'll get them.
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\n" ); document.write( "Your answer is:
\n" ); document.write( "You'll get one solution when c = 9.
\n" ); document.write( "You'll get two solutions when c < 9.
\n" ); document.write( "You'll get no solutions when c > 9.
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