document.write( "Question 216488: the difference of two whole numbersis 2. if two times the squareof the smaller number added too three times the squareof the larger numbers equal 140, find the numbers \n" ); document.write( "
Algebra.Com's Answer #163506 by drj(1380)\"\" \"About 
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The difference of two whole numbers is 2. if two times the square of the smaller number added too three times the square of the larger numbers equal 140, find the numbers.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let x be one number and x+2 be the other number.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let \"2x%5E2+\" be two times the square of the smaller number.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let 3*(x+2)^2 be three times the square of the larger number.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. The, \"2x%5E2%2B3%28x%2B2%29%5E2=140\" since two times the square of the smaller number added too three times the square of the larger numbers equal 140.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Solving yields the following steps:\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B3%28x%2B2%29%5E2=140\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B3%28x%5E2%2B4x%2B4%29=140\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B3x%5E2%2B12x%2B12=140\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B12x%2B12=140\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 140 from both sides of the equation to get a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B12x%2B12-140=140-140\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B12x-128=0\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6. To solve, we can use the quadratic equation given as \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
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\n" ); document.write( "\n" ); document.write( "where a=5, b=12, and c=-128\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"5x%5E2%2B12x%2B-128+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2812%29%5E2-4%2A5%2A-128=2704\".
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\n" ); document.write( " Discriminant d=2704 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-12%2B-sqrt%28+2704+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2812%29%2Bsqrt%28+2704+%29%29%2F2%5C5+=+4\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2812%29-sqrt%28+2704+%29%29%2F2%5C5+=+-6.4\"
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\n" ); document.write( " Quadratic expression \"5x%5E2%2B12x%2B-128\" can be factored:
\n" ); document.write( " \"5x%5E2%2B12x%2B-128+=+5%28x-4%29%2A%28x--6.4%29\"
\n" ); document.write( " Again, the answer is: 4, -6.4.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B12%2Ax%2B-128+%29\"

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\n" ); document.write( "\n" ); document.write( "Select the positive number since we want whole numbers gives x=4 and x+2=6\r
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\n" ); document.write( "\n" ); document.write( "Check...\"2x%5E2%2B3%28x%2B2%29%5E2=2%2A4%5E2%2B3%2A6%5E2=32%2B108=140\" which is a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 7. ANSWER: The numbers are 4 and 6.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit \r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit \r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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