document.write( "Question 216335: let f(x)=2x^2+3x-5 g(x)=4 solve for fog and gof \n" ); document.write( "
Algebra.Com's Answer #163492 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "To solve for fog (pronounced \"f of g\") and gof (\"pronounced g of f\") it helps to understand function notation well. When you are given a formula (or rule) for a function (like \n" ); document.write( "So when you see \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "For \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "etc. \n" ); document.write( " \n" ); document.write( "So now we are in position to figure out your problem. fog (\"f of g\") is another way of saying f(g(x)). Since g(x) = 4, f(g(x)) = f(4). And we saw above what f does to its input. It squares it, multiplies that by 2, etc. This is what it will do to 4: \n" ); document.write( " \n" ); document.write( "Now all we have to do is go through the Order of Operations (aka PEMDAS) to simplify it: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So fog = f(g(x)) = f(4) = 39 \n" ); document.write( "gof (\"g of f\") is another way of saying g(f(x)). Now, as we saw above, the g function totally ignores its input and simply returns 4 all the time. So gof = g(f(x)) = 4! \n" ); document.write( " \n" ); document.write( " |