document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216477>Question 216477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i work this problem 1/4(x-3)+5/6=7/12x+2/3<BR>\n" );
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document.write( "i am stuck, the lcd is 12 so do i divide 12 on both sides?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163474 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do i work this problem 1/4(x-3)+5/6=7/12x+2/3\r<BR>\n" );
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document.write( "i am stuck, the lcd is 12 so do i divide 12 on both sides? <BR>\n" );
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document.write( "It's not clear if it's 1/(4(x+3)) or (1/4)(x+3), but since you say the LCD is 12:<BR>\n" );
document.write( "(x+3)/4 + 5/6 = 7x/12 + 2/3<BR>\n" );
document.write( "Multiply by 12<BR>\n" );
document.write( "3(x+3) + 10 = 7x + 8<BR>\n" );
document.write( "3x+9 + 10 = 7x+8<BR>\n" );
document.write( "3x+19 = 7x+8<BR>\n" );
document.write( "4x = 11<BR>\n" );
document.write( "x = 11/4<BR>\n" );
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