document.write( "Question 216460: Find all real and complex zeros for h(x)=x^3-x^2-7x-15\r
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document.write( "P: 1,3,5,15
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document.write( "Q:1 \n" );
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Algebra.Com's Answer #163452 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! Find all real and complex zeros for \n" ); document.write( "P: 1,3,5,15 \n" ); document.write( "Q:1 \n" ); document.write( "Since the function as you given it has no rational roots, I'm going to guess that you have a typo and \n" ); document.write( "With this h(x) we can find that -3 is a rational root. To illustrate I'll use synthetic division because it will also show how to factor h(x): \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "-3 | 1 -1 -7 15\r\n" ); document.write( "---- -3 12 -15\r\n" ); document.write( " -------------------\r\n" ); document.write( " 1 -4 5 0\r\n" ); document.write( " \n" ); document.write( "The remainder, 0, tells us that h(-3) = 0. So -3 is a root of h(x). And if -3 is a root of h(x), then (x+3) is a factor of h(x). And the other factor is found in the numbers in front of the reaminder above, \"1 -4 5\", which translates into \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "For our expression, a = 1, b = -4 and c = 5. Substituting these into the formula we get: \n" ); document.write( " \n" ); document.write( "Simplifying... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "With the negative in the square root, we will have complex roots. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The 2's cancel leaving: \n" ); document.write( " \n" ); document.write( "So our three roots are: -3, 2+i and 2-i \n" ); document.write( " |