document.write( "Question 216452: How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution? \n" ); document.write( "
Algebra.Com's Answer #163438 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution? \n" ); document.write( ". \n" ); document.write( "Let x = liters of 60% acid solution to be added \n" ); document.write( "then \n" ); document.write( "20-x = liters of 75% acid solution to be added \n" ); document.write( ". \n" ); document.write( "Our equation: \n" ); document.write( ".60x + .75(20-x) = .72(20) \n" ); document.write( ".60x + 15 - .75x = 14.4 \n" ); document.write( "15 - .15x = 14.4 \n" ); document.write( "- .15x = -.6 \n" ); document.write( "x = 4 L (60% solution) \n" ); document.write( ". \n" ); document.write( "75% solution: \n" ); document.write( "20-x = 20-4 = 16 L \n" ); document.write( " |