document.write( "Question 216452: How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution? \n" ); document.write( "
Algebra.Com's Answer #163438 by nerdybill(7384)\"\" \"About 
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How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20L of a 72% solution?
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\n" ); document.write( "Let x = liters of 60% acid solution to be added
\n" ); document.write( "then
\n" ); document.write( "20-x = liters of 75% acid solution to be added
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\n" ); document.write( "Our equation:
\n" ); document.write( ".60x + .75(20-x) = .72(20)
\n" ); document.write( ".60x + 15 - .75x = 14.4
\n" ); document.write( "15 - .15x = 14.4
\n" ); document.write( "- .15x = -.6
\n" ); document.write( "x = 4 L (60% solution)
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\n" ); document.write( "75% solution:
\n" ); document.write( "20-x = 20-4 = 16 L
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