document.write( "Question 216370: A certain captain being asked how many soliders he had in his company, replied: one half of them are in camp,
\n" ); document.write( "one third in the trenches, one eighth in the hospital, and four in prison. Of how many men did his company consist?
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Algebra.Com's Answer #163377 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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one half of them are in camp,
\n" ); document.write( "one third in the trenches, one eighth in the hospital, and four in prison. Of how many men did his company consist?
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\n" ); document.write( "Let x = no. in the co
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\n" ); document.write( "x = $\"1%2F2\"$ x + $\"1%2F3\"$ x + $\"1%2F8\"$ x + 4
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\n" ); document.write( "Multiply equation by 24, get rid of the denominator, results:
\n" ); document.write( "24x = 12x + 8x + 3x + 24(4)
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\n" ); document.write( "24x = 23x + 96
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\n" ); document.write( "24x - 23x = 96
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\n" ); document.write( "x = 96 men in the co
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\n" ); document.write( "YOu can check the solution in the original equation \n" ); document.write( "

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