document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216326>Question 216326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One angle measures 12 degrees more than the other. What is the measure of the angles.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163347 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One angle measures 12 degrees more than the other. What is the measure of the angles.\r<BR>\n" );
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document.write( "Step 1.  Supplementary angles means that two angles add up to 180 degrees.\r<BR>\n" );
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document.write( "Step 2.  Let x be one angle and let x+12 be its supplementary angle and one angle measures 12 degrees more than the other\r<BR>\n" );
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document.write( "Step 3.  Then x+x+12=180 or 2x+12=180.  Subtracting 12 from both sides of the equation yields 2x=168.  Dividing by 2 to both sides yields x=84 degrees.  Then x+12=96.  Also, note that 84+96 add up to 180 degrees.\r<BR>\n" );
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document.write( "Step 4.  ANSWER:  The supplementary angles are 84 and 96 degrees.\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit \r<BR>\n" );
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document.write( "http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit \r<BR>\n" );
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document.write( "http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J </SPAN>\n" );
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