document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29547>Question 29547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x+y=1<BR>\n" );
document.write( "2x-y=2\r<BR>\n" );
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document.write( "rules say to use substitution to solve the system </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16332 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=1----(1)<BR>\n" );
document.write( "2x-y=2 ----(2)<BR>\n" );
document.write( "(1) implies x = (1-y) ----(*)(subtracting y from both the sides)<BR>\n" );
document.write( "Putting (*) in (2)<BR>\n" );
document.write( "2x-y=2 <BR>\n" );
document.write( "2(1-y)-y=2<BR>\n" );
document.write( "2-2y-y = 2<BR>\n" );
document.write( "2-3y = 2<BR>\n" );
document.write( "2-2 = 3y<BR>\n" );
document.write( "0=3y<BR>\n" );
document.write( "That is 3y = 0<BR>\n" );
document.write( "y =0/3 = 0<BR>\n" );
document.write( "Putting y=0 in (*)<BR>\n" );
document.write( "x=(1-y) = (1-0)=1<BR>\n" );
document.write( "Answer: x=1,y=0<BR>\n" );
document.write( "Verification: Putting x=1 and y=0 in (1)<BR>\n" );
document.write( "x+y =1<BR>\n" );
document.write( "LHS = x+y = 1+0 = 1 =RHS </SPAN>\n" );
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