document.write( "Question 216244: Please help me find the next number in the sequence,
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document.write( "1,7,31,127,... \n" );
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Algebra.Com's Answer #163309 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the next number in the sequence, \n" ); document.write( "1,7,31,127,... \n" ); document.write( "--- \n" ); document.write( "It looks like one less than powers of 2. \n" ); document.write( "--- \n" ); document.write( "For example: \n" ); document.write( "1st: 1 = 2^(1)-1 = 1 \n" ); document.write( "2nd: 7 = 2^(3)-1 = 7 \n" ); document.write( "3rd: 31= 2^(5)-1 = 31 \n" ); document.write( "4th: 127 = 2^(7)-1 = 127 ... \n" ); document.write( "... \n" ); document.write( "... \n" ); document.write( "nth: 2^(2n-1)-1 \n" ); document.write( "------------------------------- \n" ); document.write( "5th: 2^(9)-1 = 511 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |