document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216201>Question 216201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determine the equation of the line described. Put answer in the slope-intercept form, if possible.\r<BR>\n" );
document.write( "\n" );
document.write( "Through (6,-1), parallel to 8x-9y=111 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163287 by </B><A HREF=/tutors/aboutme.mpl?userid=bfdccheerleader16><B>bfdccheerleader16(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bfdccheerleader16><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you put your line in slope intercept form which would end up to be y=8/9x-37/3 and then the next line that goes through the points (6,-1) would also have a slope of 8/9 because the lines are parallel. next you would use the points and the slope of the 2nd line to determine the y-intercept. So you would use point-slope form and get y+1=8/9(x-6) and you would get y+1=8/9x-16/3. then subtract the one and you get y=8/9x-13/3. and that is your line that goes through the points (6,-1). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );