document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29554>Question 29554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4a(3x+5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16328 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4a(3x+5)<BR>\n" );
document.write( "=4aX(3x)+4aX(5)  (expanding)<BR>\n" );
document.write( "=12ax+20a<BR>\n" );
document.write( "Note: Normally in problems it will be the other way around.<BR>\n" );
document.write( "You will be given 12ax+20a<BR>\n" );
document.write( " and pulling 4a common we write<BR>\n" );
document.write( "12ax+20a = 4a(3x+5)<BR>\n" );
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