document.write( "Question 29566: 2x^2=72 \n" ); document.write( "
Algebra.Com's Answer #16323 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
2x^2=72 ----(1)
\n" ); document.write( "Dividing by 2
\n" ); document.write( "x^2 = 72/2 = (2X36)/2 = 36
\n" ); document.write( "x^2= 36
\n" ); document.write( "Taking the sqroot,we get
\n" ); document.write( "x = + or munus 6
\n" ); document.write( "Answer: x =6 and x = -6
\n" ); document.write( "Verification:Put x=6 in (1)
\n" ); document.write( "LHS = 2x^2 = 2X(6^2) = 2X(36) = 72 = RHS
\n" ); document.write( "Put x=-6 in (1)
\n" ); document.write( "LHS = 2x^2 = 2X[(-6)^2]= 2X36 = 72 = RHS
\n" ); document.write( "Therefore our values are correct.
\n" ); document.write( " \n" ); document.write( "
\n" );