document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216095>Question 216095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle if its supplement measures 30 degrees more than twice its complement.   Really struggling with this for some reason. can anyone explain how to try and tackle this wordy beast?! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163210 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle if its supplement measures 30 degrees more than twice its complement. <BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "A = the angle<BR>\n" );
document.write( "supplement = 180 - A<BR>\n" );
document.write( "complement = 90 - A<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "(180 - A) = 2*(90 - A) + 30<BR>\n" );
document.write( "180-A = 180 - 2A + 30<BR>\n" );
document.write( "-A = -2A + 30<BR>\n" );
document.write( "A = 30\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );