document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=216086>Question 216086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sorry but i'am not sure what this kind of problem is<BR>\n" );
document.write( "what is x?<BR>\n" );
document.write( " sqrt (3x+1)+ sqrt (2x+4)= 3 \r<BR>\n" );
document.write( "\n" );
document.write( "i subtracted>>>sqrt (2x+4) from both sides and got >>>>sqrt (3x+1)= 3 -sqrt (2x+4)<BR>\n" );
document.write( "then i squared both sides to remove the radical and got>> <BR>\n" );
document.write( "3x+1= (3-(sqrt(2x+4)(3-sqrt(2x+4)then i did that and got<BR>\n" );
document.write( "3x+1= 9-6 sqrt(2x+4) +2x+4<BR>\n" );
document.write( "then i added 9+4 and got >> 3x+1=13-6 sqrt(2x+4) +2x<BR>\n" );
document.write( "then i subtrcated 2x from each side and got>>> x+1=13-6 sqrt(2x+4)<BR>\n" );
document.write( "then i subtracted 1 from each side and got>> x=12-6sqrt(2x+4)<BR>\n" );
document.write( "added 6sqrt(2x+4) to each side and got>>> 6sqrt(2x+4)+x=12<BR>\n" );
document.write( "then i subtracted x from both sides and got>>> 6sqrt(2x+4)=12-x<BR>\n" );
document.write( "then i squared both sides to remove the radical n got<BR>\n" );
document.write( "36(2x+4)=(12-x)(12-x)<BR>\n" );
document.write( "72x+144=144-12x-12x+x^2<BR>\n" );
document.write( "72x+144= 144-24x=x^2<BR>\n" );
document.write( "-72x-144 -144-72x <BR>\n" );
document.write( "0=-96x+x^2 <BR>\n" );
document.write( "0=x^2+96<BR>\n" );
document.write( " i wanted to know from her do i plug the number into<BR>\n" );
document.write( "x=b +or- sqrt b^2-4(a)(c)divided by 2(a)  <BR>\n" );
document.write( " and i wanted to kno if u get a negative answer from this equation <BR>\n" );
document.write( "x=b +or- sqrt b^2-4(a)(c)divided by 2(a)  how do you check it because you cant square a negative in the calculator </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163207 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sorry but i'am not sure what this kind of problem is<BR>\n" );
document.write( "what is x?<BR>\n" );
document.write( "sqrt (3x+1)+ sqrt (2x+4)= 3 <BR>\n" );
document.write( "i subtracted>>>sqrt (2x+4) from both sides and got >>>>sqrt (3x+1)= 3 -sqrt (2x+4)<BR>\n" );
document.write( "then i squared both sides to remove the radical and got>> <BR>\n" );
document.write( "3x+1= (3-(sqrt(2x+4)(3-sqrt(2x+4)then i did that and got<BR>\n" );
document.write( "3x+1= 9-6 sqrt(2x+4) +2x+4<BR>\n" );
document.write( "---<BR>\n" );
document.write( "then i subtracted x from both sides and got>>> 6sqrt(2x+4)=12-x<BR>\n" );
document.write( "then i squared both sides to remove the radical n got<BR>\n" );
document.write( "36(2x+4)=(12-x)(12-x)<BR>\n" );
document.write( "72x+144=144-12x-12x+x^2<BR>\n" );
document.write( "72x+144= 144-24x+x^2<BR>\n" );
document.write( "x^2-96x = 0<BR>\n" );
document.write( "x(x-96) = 0<BR>\n" );
document.write( "x = 0 or x = 96<BR>\n" );
document.write( "----<BR>\n" );
document.write( "At this point you have to check these \"solutions\"<BR>\n" );
document.write( "in the original equation.  If x = 0 gives you<BR>\n" );
document.write( "a true statement x=0 IS a solution.<BR>\n" );
document.write( "Similarly you need to check x = 96.<BR>\n" );
document.write( "------------------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );