document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29568>Question 29568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perform the indicated operations and write the answer in standard form:  (4-i)^2+2(3-2i)-4  I don't even know where to begin.  Help!  Do I take care of what is inside the parenthesis first?  <BR>\n" );
document.write( "Mary </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16320 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4-i)^2+2(3-2i)-4 <BR>\n" );
document.write( "=[(4)^2+2X(4)X(-i)+(-i)^2]+[2X3-2X(3i)]-4<BR>\n" );
document.write( "[using (a+b)^2 = a^2 +2ab+b^2 where here a = 4 and b= (-i)]<BR>\n" );
document.write( "=[16-8i+i^2]+6-4i-4<BR>\n" );
document.write( "=(16-8i-1)+6-4i-4<BR>\n" );
document.write( "=(16-1+6-4)+(-8i-4i)  (grouping like terms)<BR>\n" );
document.write( "=17-12i<BR>\n" );
document.write( "Answer: (4-i)^2+2(3-2i)-4 = 17-12i<BR>\n" );
document.write( "Note:(4-i)^2 can also be expanded using <BR>\n" );
document.write( "(a-b)^2 = a^2-2ab+b^2  where here a=4,b= i and therefore <BR>\n" );
document.write( "a^2 = 4^2 = 16, -2ab = -2X4x(i) = -8i and b^2 = (i)^2 = i^2 = -1 so that <BR>\n" );
document.write( "(4-i)^2 =4^2-2X4x(i)+ (i)^2  =16-8i-1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );