document.write( "Question 216026: A bar of metal contains 10% silver. Another bar contains 15% silver. How many kilograms of each must be taken to make a 10 kilogram bar containing 12% silver. \n" ); document.write( "
Algebra.Com's Answer #163172 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Let x = amt at 10%,,,and y= amt at 15% \n" ); document.write( ". \n" ); document.write( "(1) x + y = 10,,,,,,,or y=10-x \n" ); document.write( ". \n" ); document.write( "(2) .10*x +.15*y = .12*10,,,,,,,,,silver balance \n" ); document.write( ". \n" ); document.write( "subst from (1) \n" ); document.write( ". \n" ); document.write( ".1x +.15(10-x) = .12*10 \n" ); document.write( ". \n" ); document.write( ".1x +1.5 - .15x = 1.2,,,,,combine like terms \n" ); document.write( ". \n" ); document.write( "-.05x = -.3 \n" ); document.write( ". \n" ); document.write( "x=6 kg,,,,,,,,,,,,,,y=10-6=4 kg \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "check,,,,,.1(6) +.15(4) = .6 + .6 =1.2 = .12*10 ,,,,,,ok \n" ); document.write( " |