document.write( "Question 215929This question is from textbook
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document.write( ": Find a number that is 68 greater than three times its opposite \n" );
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Algebra.Com's Answer #163161 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! Find a number that is 68 greater than three times its opposite. \n" ); document.write( "Let x = \"a number\". \n" ); document.write( "then the opposite of that number = -x \n" ); document.write( "and three times the opposite = 3(-x) = -3x \n" ); document.write( "Now we do a \"translation\" of \"a number is 68 greater than three times its opposite\". When doing a translation from English to Algebra, forms of the verb \"to be\" (is, are, was, were, etc.) translate into equal signs. \n" ); document.write( "\"a number is 68 greater than three times its opposite\" \n" ); document.write( " x = 68 + (-3x) \n" ); document.write( "Now we have an equation we can solve. As usual there are many ways to solve this. One way would be: Add 3x to both sides: \n" ); document.write( "x + 3x = 68 + (-3x) + 3x \n" ); document.write( "Add like terms: \n" ); document.write( "4x = 68 + 0 \n" ); document.write( "4x = 68 \n" ); document.write( "Divide both sides by 4: \n" ); document.write( " \n" ); document.write( "Cancel common factors \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "leaving \n" ); document.write( " \n" ); document.write( "Simplifying we get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |