document.write( "Question 215929This question is from textbook
\n" ); document.write( ": Find a number that is 68 greater than three times its opposite \n" ); document.write( "
Algebra.Com's Answer #163161 by jsmallt9(3758)\"\" \"About 
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Find a number that is 68 greater than three times its opposite.

\n" ); document.write( "Let x = \"a number\".
\n" ); document.write( "then the opposite of that number = -x
\n" ); document.write( "and three times the opposite = 3(-x) = -3x
\n" ); document.write( "Now we do a \"translation\" of \"a number is 68 greater than three times its opposite\". When doing a translation from English to Algebra, forms of the verb \"to be\" (is, are, was, were, etc.) translate into equal signs.
\n" ); document.write( "\"a number is 68 greater than three times its opposite\"
\n" ); document.write( " x = 68 + (-3x)
\n" ); document.write( "Now we have an equation we can solve. As usual there are many ways to solve this. One way would be: Add 3x to both sides:
\n" ); document.write( "x + 3x = 68 + (-3x) + 3x
\n" ); document.write( "Add like terms:
\n" ); document.write( "4x = 68 + 0
\n" ); document.write( "4x = 68
\n" ); document.write( "Divide both sides by 4:
\n" ); document.write( "\"%284x%29%2F4+=+%2868%29%2F4\"
\n" ); document.write( "Cancel common factors
\n" ); document.write( "\"%284%2Ax%29%2F%284%2A1%29+=+%2817%2A4%29%2F%284%2A1%29\"
\n" ); document.write( "
\n" ); document.write( "leaving
\n" ); document.write( "\"x%2F1+=+17%2F1\"
\n" ); document.write( "Simplifying we get:
\n" ); document.write( "\"x+=+17\"
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