document.write( "Question 215999: Tom is half as old as Ellen was three years ago.
\n" ); document.write( "In 10 years, Ellen will be one-and-one-half times as old as Tom.\r
\n" ); document.write( "\n" ); document.write( "Would you please show me the formula to use? And the answer? \r
\n" ); document.write( "\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #163158 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
Tom is half as old as Ellen was three years ago.
\n" ); document.write( "In 10 years, Ellen will be one-and-one-half times as old as Tom.\r
\n" ); document.write( "\n" ); document.write( "Would you please show me the formula to use? And the answer? \r
\n" ); document.write( "\n" ); document.write( "I probably need more info but here is the problem set-up.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 1. Let \"x\" be Tom's current age and let \"y\" be Ellen's age\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 2. Let \"x-3\" be Tom's age three years ago and \"y-3\" be Ellen's age three years ago\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 3. Let \"y-3=2%28x-3%29\" be Ellen's age three years ago since Tom is half of Ellen's age three years ago. Simply this equation as follows\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-3=2%28x-3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-3=2x-6\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add 6-y to both sides of the equation to isolate x and y terms on one side and numbers on the right side\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-3%2B6-y=2x-6%2B6-y\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3=2x-y\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x-y=3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 4. Let \"y%2B10=3%28x%2B10%29%2F2\" be Ellen's age in ten years since Ellen will be one and one half times as old as Tom where \"1.5=3%2F2\", x+10 is Tom's age in ten years, and y+10 is Ellen's age in ten years.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply by 2 to both sides of the equation to get rid of denominator\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28y%2B10%29=2%2A3%28x%2B10%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2y%2B20=3x%2B30\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract 3x-20 to both sides of the equation\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2y%2B20-3x-20=3x%2B30-3x-20\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-3x%2B2y=10\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 5. Now we have a linear system of equations from Steps 3 and 4 and is shown below:\r
\n" ); document.write( "\n" ); document.write( "\"2x-y=3\"
\n" ); document.write( "\"-3x%2B2y=10\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 6. Now solve the linear system of equations in Step 5 using substitution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++2%5Cx+%2B+-1%5Cy+=+3%2C%0D%0A++++-3%5Cx+%2B+2%5Cy+=+10+%29%0D%0A++\"We'll use substitution. After moving -1*y to the right, we get:
\n" ); document.write( " \"2%2Ax+=+3+-+-1%2Ay\", or \"x+=+3%2F2+-+-1%2Ay%2F2\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"-3%2A%283%2F2+-+-1%2Ay%2F2%29+%2B+2%5Cy+=+10\" and simplify: So, we know that y=29. Since \"x+=+3%2F2+-+-1%2Ay%2F2\", x=16.
\n" ); document.write( "
\n" ); document.write( " Answer: \"system%28+x=16%2C+y=29+%29\".
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So x=16 and y=29.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check the ages three ago\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-3=16-3=13\" and \"y-3=29-3=26\" where Ellen is twice the age of Tom three years ago...so this is a true statement.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check the ages ten years from now.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2B10=16%2B10=26\" and \"y%2B10=29%2B10=39\" or \"39=3%2A26%2F2=39\" which is another true statement.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 7. So Tom is 16 years old and Ellen is 29 years old.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit \r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit \r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV/courses/Trigonometry.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );