document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215921>Question 215921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please solve each step and show your work. \r<BR>\n" );
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document.write( "Part 11: 5^(2x+1)=8\r<BR>\n" );
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document.write( "   Step 1: Take the common logarithm of both sides of the equation. Use the power property to bring the exponent, (2x+1), down as a factor.  \r<BR>\n" );
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document.write( "   Step 2: Solve the equation from step 1 for x. Round your final answer to the nearest hundreth. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163151 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5^(2x+1)=8 <BR>\n" );
document.write( "Step 1: Take the common logarithm of both sides of the equation. Use the power property to bring the exponent, (2x+1), down as a factor. <BR>\n" );
document.write( "Step 2: Solve the equation from step 1 for x. Round your final answer to the nearest hundreth. <BR>\n" );
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document.write( "(2x+1)*log(5) = log(8)<BR>\n" );
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document.write( "2x+1 = log(8)/log(5) = ~ 1.29203<BR>\n" );
document.write( "2x = 0.29203<BR>\n" );
document.write( "x = 0.146 </SPAN>\n" );
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