document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215952>Question 215952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me in this problem.\r<BR>\n" );
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document.write( "Mark is two-thirds as old as Helen. In seven years, Mark will be three-fourths as old as Helen. How old are they now?\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163133 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For now, Mark is 2/3 of Helen, so let us say Mark is 2x, therefore Helen is 3x.\r<BR>\n" );
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document.write( "In seven years, 2x+7 = 3(3x+7)/4 or 4(2x+7) = 3(3x+7)\r<BR>\n" );
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document.write( "Giving 8x+28 = 9x+21\r<BR>\n" );
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document.write( "Solved gives x = 7\r<BR>\n" );
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document.write( "Let us test it:\r<BR>\n" );
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document.write( "Now: Mark is 14 and Helen is 21 (two thirds of  21 = 14)\r<BR>\n" );
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document.write( "Add 7: Mark will be 21 and Helen will be 28 (21 is three quarters of 28) </SPAN>\n" );
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