document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215931>Question 215931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The question: The product of two negative numbers is 90. If x is one of the numbers, write their sum S as a function of x.\r<BR>\n" );
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document.write( " I'm not quite sure how it would be solved. The part that says \"...their sum S as a function of x\" is what confused me. Anyone who is willing to help is welcome to! <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163132 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90=x*y y is the other negative number.<BR>\n" );
document.write( "x=90/y<BR>\n" );
document.write( "S=x+y<BR>\n" );
document.write( "S=x+90/y<BR>\n" );
document.write( "x=S-90/y ans. </SPAN>\n" );
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