document.write( "Question 215948This question is from textbook Longman mathematics for IGCSE book1
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document.write( ": a-A cross- channel hovercraft ferry leaves Dover harbour at 9am travelling at 35km/hour. Find an equation giving d (the distance travelled in km) in terms of t (the time in hours after 9am). Plot the graph of this equatiopn for 0
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document.write( "Please answer both of the parts. I am having a serious problem in this question.
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document.write( "Thankyou ver very much indeed.
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Algebra.Com's Answer #163127 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a-A cross- channel hovercraft ferry leaves Dover harbour at 9am travelling at 35km/hour. \n" ); document.write( "Find an equation giving d (the distance traveled in km) in terms of t (the time in hours after 9am). \n" ); document.write( "d = 35t \n" ); document.write( " Plot the graph of this equation for 0<1. \n" ); document.write( "for t = 1 hr; d = 35 \n" ); document.write( "for t = 2 hr; d = 70 \n" ); document.write( "Plot two points; x=1; y=35; and x=2; y=70 \n" ); document.write( " \n" ); document.write( "you can label your graph as 0 is 9AM; 1 is 10Am, etc \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "b-As the hovercraft leaves the harbour, the captain sees a car ferry 5 km ahead traveling in the same direction at 15 km/hour. Find an equation for d in terms of t for the car ferry. \n" ); document.write( "Since it has a 5 km head start, the equation is d = 15t + 5 \n" ); document.write( "Plot this one the same way: t = 1; d=20; t = 2; d = 35 \n" ); document.write( ": \n" ); document.write( " Plot the graph of this equation, and find when the hovercraft catches up with the car ferry. \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You can solve the two equations, when they are both the same distance \n" ); document.write( "35t = 15t + 5 \n" ); document.write( "35t - 15t = 5 \n" ); document.write( "20t = 5 \n" ); document.write( "t = \n" ); document.write( "t = \n" ); document.write( ": \n" ); document.write( "Did I make this understandable to you? ankor@att.net \n" ); document.write( ": \n" ); document.write( "To find the dist, substitute \n" ); document.write( "we can use .25 hr \n" ); document.write( "d = 35t \n" ); document.write( "d = 35 * .25 \n" ); document.write( "d = 8.75 km \n" ); document.write( "or \n" ); document.write( "d = 15t + 5 \n" ); document.write( "d = 15(.25) + 5 \n" ); document.write( "d = 3.75 + 5 \n" ); document.write( "d = 8.75 km \n" ); document.write( "; \n" ); document.write( "Which you would expect when both vessels are at the same point in 15 min \n" ); document.write( "Change the scale in the graph to see it (the +x axis represents 1 hr) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |