document.write( "Question 215962This question is from textbook
\n" ); document.write( ": An old water pump can fill up a large trough in 10 minutes, but a second, newer pump takes only 3 minutes and 20 seconds to fill the trough. How long would it take to fill the trough using both pumps at the same time? \n" ); document.write( "
Algebra.Com's Answer #163118 by nerdybill(7384)\"\" \"About 
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An old water pump can fill up a large trough in 10 minutes, but a second, newer pump takes only 3 minutes and 20 seconds to fill the trough. How long would it take to fill the trough using both pumps at the same time?
\n" ); document.write( ".
\n" ); document.write( "Convert rate to seconds:
\n" ); document.write( "Old pump:
\n" ); document.write( "fill trough per 10 minutes
\n" ); document.write( "is equivalent
\n" ); document.write( "fill trough per 600 seconds
\n" ); document.write( ".
\n" ); document.write( "New pump:
\n" ); document.write( "fill trough per 3 minutes 20 seconds
\n" ); document.write( "is equivalent
\n" ); document.write( "fill trough per 200 seconds
\n" ); document.write( ".
\n" ); document.write( "Let x = seconds it takes for both pump
\n" ); document.write( "then
\n" ); document.write( "x(1/600 + 1/200) = 1
\n" ); document.write( "Multiplying both sides by 600:
\n" ); document.write( "x(1 + 3) = 600
\n" ); document.write( "4x = 600
\n" ); document.write( "x = 150 seconds
\n" ); document.write( ".
\n" ); document.write( "So, for both pumps to fill the trough:
\n" ); document.write( "2 minutes 30 seconds
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